Method Overloading

• Method Overloading

  Same named method and different number of parameters.

  • 예제1 - 숫자들의 sum 구하기

    • 안 좋은 예

    public static int sumTwoNum(int a, int b) {
        return a + b;
    }
    
    public static int sumThreeNum(int a, int b, int c) {
        return a + b + c;
    }
    
    public static int sumFourNum(int a, int b, int c, int d) {
        return a + b + c + d;
    }
    

    메소드 이름이 다 다르기 때문에 복잡하고 기억하기 어렵다.

     

    • Overloading

    public static int sum(int a, int b) {
        return a + b;
    }
    
    public static int sum(int a, int b, int c) {
        return a + b + c;
    }
    
    public static int sum(int a, int b, int c, int d) {
        return a + b + c + d;
    }
    

    Overloading하면 읽기 쉽고 기억하기 훨씬 쉽다.

   

  • 예제2

  package com.Hazel;
  
  public class Main {
  
      public static void main(String[] args) {
          calcFeetAndInchesToCentimeters(50);
      }
  
      public static double calcFeetAndInchesToCentimeters(double feet, double inches) {
          if(feet < 0 || inches < 0 || inches > 12) {
              return -1;
          }
  
          double centimeters = feet * 12 * 2.54;
          centimeters += inches * 2.54;
          System.out.println(feet + " feet and " + inches + " inches = " + centimeters + " centimeters" );
          return centimeters;
      }
  
      public static double calcFeetAndInchesToCentimeters(double inches) {
          if(inches < 0) {
              return -1;
          }
          double feet = (int) inches / 12;
          double remain =  inches % 12;
          System.out.println(inches + " is equal to " +  feet + " feet and " + remain + " inches" );
          return calcFeetAndInchesToCentimeters(feet, remain);
      }
  
  }